Question #8c1a7

Question

1897 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-04T20:01:30

The correct equilibrium expression is #K_text(eq) = (["NH"_3]^2)/(["N"_2]["H"_2]^3)#.

An equilibrium constant expression is written in the form

#K_text(eq) = (["Products"])/(["Reactants"])#

where the concentration of each product and of each reactant is raised to a power equal to its coefficient in the balanced equation.

Thus, for the reaction

#"N"_2"(g)" + "3H"_2"(g)" ⇌"2NH"_3"(g)"#

the equilibrium expression is

#K_text(eq) = (["NH"_3]^2)/(["N"_2]["H"_2]^3)#