Question #eae8c
1 Answer
Aug 4, 2017
Lead(IV) oxide is
Explanation:
With lead(IV) oxide, we're given that
If we switch these numbers to the opposite subscript, we would indeed obtain
#overbrace("Pb")^(color(red)(bb(4+))) + overbrace("O")^(color(green)(bb(2-))) = ul("Pb"_(color(green)(bb(2)))"O"_(color(red)(bb(4)))#
HOWEVER, ionic compounds will have their formula as the smallest whole number ratios of the subscripts. Each subscript here can be divided by
#color(blue)(ulbar(|stackrel(" ")(" ""PbO"_2" ")|)#