Question #cec3a
1 Answer
Here's what I got.
Explanation:
The idea here is that you're performing a serial dilution, so you should be aware of the fact that the overall dilution factor will be equal to the product of the dilution factors of each individual dilution.
#"DF"_"overall" = "DF"_1 xx "DF"_2 xx ... xx "DF"_n#
As you know, the dilution factor can be calculated by dividing the volume of the diluted solution by the volume of the concentrated solution.
#"DF" = V_"diluted"/V_"concentrated"#
In your case, you're performing
#"DF" = ((1 + 9)color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("mL")))) = 10#
That is the case because, for each dilution, the volume of the concentrated solution is equal to
So, you can say that after
#"DF"_"8 dilutions" = overbrace(10 xx 10 xx... xx 10)^(color(blue)("8 times")) = 10^8#
Now, the dilution factor also tells you the ratio that exists between the concentration of the concentrated solution and the concentration of the diluted solution.
For the overall dilution, you have
#"DF"_ "8 dilutions" = c_"initial"/c_"final"#
This means that the final concentration of the solution will be
#c_"final" = c_"initial"/10^8#
In your case, this is equivalent to
#c_"final" = "0.1 M"/10^8 = 10^(-9)# #"M"#
Now, for all intended purposes and based on the number of significant figures that you have for your values, you can go ahead and say that the
It's worth mentioning that the actual