Why do ammonium salts give solutions whose $p H < 7$ $pH<7$ ?

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Why do ammonium salts give solutions whose $p H < 7$ $pH<7$ ?

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Answer 1 · 2017-08-13T13:32:59

The ammonium chloride salt undergoes ionization in water......

Explanation:

$N H_{4} C l (s) H_{2} O - - \to N H_{4}^{+} + C l^{-}$ $NH_4Cl(s) stackrel(H_2O)rarrNH_4^+ + Cl^-$

The ammonium ion also acts as a weak acid in water to give equilibrium quantities of ammonia, $N H_{3} (a q)$ $NH_3(aq)$ and the hydronium ion, $H_{3} O^{+}$ $H_3O^+$ ....

$N H_{4}^{+} + H_{2} O (l) ⇌ N H_{3} (a q) + H_{3} O^{+}$ $NH_4^+ +H_2O(l) rightleftharpoonsNH_3(aq) +H_3O^+$

The equilibrium lies to the LEFT as written, but it does operate. $p K_{a} = 9.25$ $pK_a=9.25$ for ammonium ion.

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Why do ammonium salts give solutions whose $p H < 7$ $pH<7$ ?

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Why do ammonium salts give solutions whose pH<7pH<7?

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Why do ammonium salts give solutions whose $p H < 7$ $pH<7$ ?