How many electrons are found in a sample of dioxygen gas contained in a "0.448 L" container at STP?
3 Answers
Explanation:
The no of electrons present in448 ml of O2 at STP
At STP conditions 1 mole of O2 gas =
So,
=
See.
Explanation:
Hence,
Here,
About
Assuming your definition of STP is
PV = nRT for pressure
P , volumeV , molsn , temperatureT , and universal gas constantR .
Rearranging, we get...
V/n = (RT)/P
= (("0.082057 L"cdot"atm/mol"cdot"K")("273.15 K"))/"1 atm"
= "22.414 L/mol"
So, with this molar volume, we compare ratios:
"0.448 L"/("x mols") = "22.414 L"/"mol"
=> n_("O"_2) = "0.0200 mols"
Each
"0.0200 mols O"_2 harr "0.320 mols e"^(-)
And thus, the number of electrons is given by
color(blue)("Number of electrons") = "0.320 mols e"^(-) xx 6.0221413 xx 10^(23) "mol"^(-1)
= ulcolor(blue)(1.93 xx 10^(23)color(white)(.)"e"^(-))