Question

What is the percentage of oxygen in sulfuric acid?

Answer 1

The percentage of oxygen in sulfuric acid is 65.254%.

Explanation:

The chemical formula for sulfuric acid, `"H"_2"SO"_4`, indicates that in one mole of sulfuric acid, there are four moles of oxygen atoms. In order to calculate the percentage of oxygen in sulfuric acid, you need to divide the mass of oxygen in one mole of sulfuric acid by the molar mass of sulfuric acid and multiply by 100.

Molar mass `"H"_2"SO"_4="98.072 g/mol"`

Mass of O: `4xx"15.999 g/mol"="63.996 g/mol"`

Percentage O

`(63.996color(red)cancel(color(black)("g/mol")))/(98.072color(red)cancel(color(black)("g/mol")))xx100="65.254% O"`