How to write and balance the equation for the reaction: sodium fluoride plus copper(II) nitrate produces sodium nitrate plus copper(II) fluoride?

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How to write and balance the equation for the reaction: sodium fluoride plus copper(II) nitrate produces sodium nitrate plus copper(II) fluoride?

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Answer 1 · 2017-08-20T04:03:41

Refer to the explanation.

Explanation:

You need to determine the formulas first.

sodium fluoride: $NaF$ $"NaF"$

copper(II) nitrate: ${Cu(NO}_{3})_{2}$ $"Cu(NO"_3)"_2$

sodium nitrate: ${NaNO}_{3}$ $"NaNO"_3$

copper(II) fluoride: ${CuF}_{2}$ $"CuF"_2$

${NaF + Cu(NO}_{3})_{2}$ $"NaF + Cu(NO"_3)_2"$ $\to$ $rarr$ ${NaNO}_{3} + {CuF}_{2}$ $"NaNO"_3 + "CuF"_2$

All of these compounds are ionic. If we look first at the polyatomic ion ${NO}_{3}^{-}$ $"NO"_3"^-$ as a whole, we can see that there are two of them on the lefthand side and one on the righthand side. So you need to place a coefficient of $2$ $2$ in front of ${NaNO}_{3}$ $"NaNO"_3"$ . That will cause the $NaF$ $"NaF"$ to be unbalanced, so you need to place a coefficient of $2$ $2$ in front of $NaF$ $"NaF"$ . This will balance the fluoride ions, and you're done.

${2NaF + Cu(NO}_{3})_{2}$ $"2NaF + Cu(NO"_3)_2"$ $\to$ $rarr$ ${2NaNO}_{3} + {CuF}_{2}$ $"2NaNO"_3 + "CuF"_2$

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How to write and balance the equation for the reaction: sodium fluoride plus copper(II) nitrate produces sodium nitrate plus copper(II) fluoride?

1 Answer

Explanation:

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