A vernier calipers has an error of $2 %$ $2%$ in length, $1 %$ $1%$ in breadth and $3 %$ $3%$ in thickness, What is the maximum percentage error in measuring volume with it?

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Answer 1 · 2017-08-20T07:36:59

Percentage error in volume is $6.11 %$ $6.11%$

We have $Volume = Length \times Breadth \times Thickness$ $"Volume"="Length"xx"Breadth"xx"Thickness"$

As error in measurement using vernier calipers is $2 %$ $2%$ in length, $1 %$ $1%$ in breadth and $3 %$ $3%$ in thickness,

percentage error in volume would be given by

$1.02 \times 1.01 \times 1.03 = 1.061106$ $1.02xx1.01xx1.03=1.061106$

i.e. $6.1106 ≅ 6.11 %$ $6.1106~=6.11%$

A vernier calipers has an error of 2%2%2% in length, 1%1%1% in breadth and 3%3%3% in thickness, What is the maximum percentage error in measuring volume with it?