Question #7f3c3

1 Answer
Aug 20, 2017

69.2 "L N"_2

Explanation:

We're asked to find the volume (in liters) occupied by 86.5 "g N"_2.

I'll assume the conditions are standard temperature and pressure.

If these conditions are 1 "atm" and 273.15 "K" (0 ""^"o""C"), then one mole of an (ideal) gas occupies a volume of 22.4 "L".

With that in mind, let's first convert from grams of nitrogen to moles, using its molar mass:

86.5cancel("g N"_2)((1color(white)(l)"mol N"_2)/(28.013cancel("g N"_2))) = color(red)(ul(3.09color(white)(l)"mol N"_2

Now, we use the above conversion factor

ul(1color(white)(l)"mol" = 22.4color(white)(l)"L"

to convert from moles to liters:

color(red)(3.09)cancel(color(red)("mol N"_2))((22.4color(white)(l)"L N"_2)/(1cancel("mol N"_2))) = color(blue)(ulbar(|stackrel(" ")(" "69.2color(white)(l)"L N"_2" ")|)

Therefore, 86.5 grams of nitrogen occupies a volume of color(blue)(69.2color(white)(l)"liters".