We know that #K_w=10^(-14)# at #298*K#. How would #K_w# evolve at #373*K#?

2 Answers
anor277
Aug 23, 2017

Would you not expect it to be greater than #K_w# at #298*K#?

Explanation:

We know that at #298*K#,

#2H_2OrightleftharpoonsH_3O^+ + HO^-#, #K_w=10^-14=[H_3O^+][HO^-]#.

This site relates that #K_w=51.3xx10^-14# at #373*K#. Because this is manifestly a BOND-BREAKING reaction, we would expect that the given equilibrium LIES farther to the right. Does the given value support this expectation........?

What is #pH# at this temperature?

Michael
Aug 23, 2017

The link below gives you information on this.

Explanation:

Related questions
See all questions in Equilibrium Constants
Impact of this question
1439 views around the world
You can reuse this answer
Creative Commons License