If the density of a material is $0.88 \cdot g \cdot m L^{- 1}$ $0.88gmL^-1$ , what is the material?

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If the density of a material is $0.88 \cdot g \cdot m L^{- 1}$ $0.88gmL^-1$ , what is the material?

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Answer 1 · 2017-09-03T17:27:31

In effect you propose to identify a chemical based solely on its density.....?

Explanation:

Well we can work out the density.....

$ρ = \frac{Mass}{Volume} = \frac{8.184 \cdot g}{10.5 \cdot m L - 1.2 \cdot m L} = 0.88 \cdot g \cdot m L^{- 1}$ $rho="Mass"/"Volume"=(8.184*g)/(10.5*mL-1.2*mL)=0.88*g*mL^-1$ .

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If the density of a material is $0.88 \cdot g \cdot m L^{- 1}$ $0.88gmL^-1$ , what is the material?

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If the density of a material is $0.88 \cdot g \cdot m L^{- 1}$ $0.88gmL^-1$ , what is the material?