How would the volume if a gas in a piston under $14 \cdot bar$ $14"bar"$ pressure with a volume of $312 \cdot m L$ $312mL$ , were reduced in pressure to $7 \cdot bar$ $7*"bar"$ pressure?

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How would the volume if a gas in a piston under $14 \cdot bar$ $14"bar"$ pressure with a volume of $312 \cdot m L$ $312mL$ , were reduced in pressure to $7 \cdot bar$ $7*"bar"$ pressure?

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Answer 1 · 2017-09-04T14:30:50

Would it not be around $7 \cdot bar$ $7*"bar"$ .........?

Explanation:

Old Boyle's Law holds that given constant temperature, and for a given amount of gas..... $P \propto \frac{1}{V}$ $Pprop1/V$ ........

Else, $P V = k$ $PV=k$ , and thus solving for $k$ $k$ at different pressures and volumes......

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

And so...... $P_{2} = \frac{P_{1} V_{1}}{V_{2}} = \frac{14 \cdot bar \times 312 \cdot m L}{652 \cdot m L} = ? ? \cdot bar$ $P_2=(P_1V_1)/V_2=(14*"bar"xx312*mL)/(652*mL)=??*"bar"$ .

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How would the volume if a gas in a piston under $14 \cdot bar$ $14"bar"$ pressure with a volume of $312 \cdot m L$ $312mL$ , were reduced in pressure to $7 \cdot bar$ $7*"bar"$ pressure?

1 Answer

Explanation:

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Science

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How would the volume if a gas in a piston under 14⋅bar14*"bar" pressure with a volume of 312⋅mL312*mL, were reduced in pressure to 7⋅bar7*"bar" pressure?

1 Answer

Explanation:

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How would the volume if a gas in a piston under $14 \cdot bar$ $14"bar"$ pressure with a volume of $312 \cdot m L$ $312mL$ , were reduced in pressure to $7 \cdot bar$ $7*"bar"$ pressure?