Question #e96d5

1 Answer

0.932 xx 10^(-5)

Explanation:

It's so easy to understand.

The only thing we have to know is that 1 mol of any gas has a volume of 24.04 L at NTP (Normal Temperature and Pressure)

Here the volume is given as 2.24 mL.

                     1 L = 1000 mL

Hence "1 mL" = 10^(-3) " L"

"2.24 mL" = 2.24 xx 10^(-3) " L"

"24.04 L of CO"_2 = "1 mol of CO"_2 (at NTP only)

2.24 xx 10^(-3) " L CO"_2 xx ("1 mol CO"_2)/("24.04 L CO"_2) = 9.32 xx 10^(-5) " mol CO"_2

Therefore 2.24 mL "CO"_2 at NTP contains 0.932 xx 10^(-5) " mol CO"_2.