What volume of ammonia may be prepared from a 1*g1g mass of dinitrogen gas?

1 Answer
Sep 9, 2017

Approx. 1*L1L of ammonia............

Explanation:

We need (i) a stoichiometric equation.....

1/2N_2(g) + 3/2H_2(g)rightleftharpoonsNH_3(g)12N2(g)+32H2(g)NH3(g)

And (ii) we need equivalent quantities of dinitrogen gas.....

-=(1.4*g)/(28.01*g*mol^-1)=0.050*mol1.4g28.01gmol1=0.050mol with respect to N_2N2.

Given the equation I can make AT MOST 0.100*mol0.100mol with respect to ammonia........Agreed?

Since an ideal gas has a molar volume at STP of 22.4*L*mol^-122.4Lmol1 (or whatever your syllabus says), we gots a volume of....

22.4*L*mol^-1xx0.05*mol~=1*L22.4Lmol1×0.05mol1L