The net force on an object of $14000 N$ $14000"N"$ causes it to accelerate at a rate of $5 m / s^{2}$ $5"m"//"s"^2$ . What is the mass of the object?

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Answer 1 · 2017-09-12T02:49:01

$m = 2800 kg$ $m=2800"kg"$

By Newton's second law, force is given by the product of an object's mass and acceleration as:

${\to F}_{net} = m \to a$ $vecF_"net"=mveca$

Which we can solve for mass (taking magnitudes) as:

$\Rightarrow m = \frac{F}{a}$ $=>m=F/a$

We are given:

Therefore, we have:

$m = \frac{14000 N}{5 m / s^{2}}$ $m=(14000"N")/(5"m"//"s"^2)$

$\Rightarrow m = 2800 kg$ $=>color(blue)(m=2800"kg")$

And we can check that the units work out, as we should get our final mass in kilograms.

$k g = \frac{\frac{k g m}{s^{2}}}{\frac{m}{s^{2}}}$ $kg=((kgm)/s^2)/(m/s^2)$

$=>kg=(kgcancelm)/cancels^2*cancels^2/cancelm$

$=>kg=kg$

The net force on an object of 14000"N"14000N14000"N" causes it to accelerate at a rate of 5"m"//"s"^25m/s25"m"//"s"^2. What is the mass of the object?