What is the #"molality"# of a #4.00g# mass of sodium chloride dissolved in #100mL# of water?

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Answer 1 · 2017-09-13T04:57:39

#"Molality"-="Moles of solute"/"Kilograms of solvent"~=0.7*mol*kg^-1#

And so here #"molality"=((4.00*g)/(58.44*g*mol^-1))/(100*gxx10^-3*kg*g^-1)=??*mol*kg^-1#.

At these concentrations, #"molality"# would be little different to #"molarity"="Moles of solute"/"Litres of solution"#

What is the #"molality"# of a #4.00*g# mass of sodium chloride dissolved in #100*mL# of water?