A hydrocarbon has an empirical formula of CH_2CH2, and a molecular mass of 42*g*mol^-142gmol1. What is the hydrocarbon?

1 Answer
Sep 18, 2017

Well we got propylene or cyclopropane.....i.e. C_3H_6C3H6....

Explanation:

The molecular formula is always a whole number multiple of the empirical formula....

And thus ...........

underbrace(12.01*g*mol^-1+2xx1.01*g*mol^-1)_"empirical formula"xxn=underbrace(42*g*mol^-1)_"molecular mass"

And so n=(42.0*g*mol^-1)/(12.01*g*mol^-1+2xx1.01*g*mol^-1)=3

And so the molecular formula is 3xxCH_2-=C_3H_6....and this is either propylene, H_3C-CH=CH_2 or "cyclopropane".