What is the density of a $0.196 \cdot g$ $0.196g$ mass of gas, confined to a $100 \cdot m L$ $100mL$ volume?

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Answer 1 · 2017-09-15T17:31:36

$.00196 \frac{g}{m l}$ $.00196g/(ml)$

Density is mass over volume. (Mass per unit volume).

So...

$\frac{0.196 g}{100 m l} or .00196 \frac{g}{m l}$ $(0.196g)/(100 ml) or .00196g/(ml)$

Answer 2 · 2017-09-15T17:32:08

Well, $ρ = \frac{Mass}{Volume}$ $rho="Mass"/"Volume"$

And so we simply work out the quotient.....

$ρ = \frac{0.196 \cdot g}{100 \cdot m L} = 1.96 \times 10^{- 3} \cdot g \cdot m L^{- 1}$ $rho=(0.196*g)/(100*mL)=1.96xx10^-3*g*mL^-1$ .....

What is the density of a 0.196⋅g0.196*g mass of gas, confined to a 100⋅mL100*mL volume?