Question

Evaluate the integral ? `int pi (cos (2pix))/(sin(2pix)) dx`

Answer 1

`int \ pi (cos (2pix))/(sin(2pix)) \ dx = 1/2 ln |sin2pix| + C`

Explanation:

`int \ pi (cos (2pix))/(sin(2pix)) \ dx = pi \ int \ cot (2pix) \ dx`
`" " = pi \ (ln |sin2pix|)/(2pi) + C`
`" " = 1/2 ln |sin2pix| + C`