Question #c4c31

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Question #c4c31

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Answer 1 · 2017-10-13T01:58:08

Seven US Dollars $($ 7)$ $($7)$ .

Explanation:

Since

$1 penny = $0.01$ $"1 penny = $0.01"$

$1 nickel = $0.05$ $"1 nickel = $0.05"$

$1 dime = $0.10$ $"1 dime = $0.10"$

$1 quarter = $0.25$ $"1 quarter = $0.25"$

you have

$15 pennies = ($ 0.01 \times 15) = $ 0.15$ $"15 pennies" = ($0.01xx15)= $0.15$

$7 nickels = ($ 0.05 \times 7) = $ 0.35$ $"7 nickels" = ($0.05xx7)= $0.35$

$15 dimes = ($ 0.10 \times 15) = $ 1.50$ $"15 dimes" = ($0.10xx15)= $1.50$

$20 quarters = ($ 0.25 \times 20) = $ 5$ $"20 quarters" = ($0.25xx20)= $5$

Let's add our results next:

$$ (0.15 + 0.35 + 1.50 + 5.00) = $ 7$ $$(0.15+0.35+1.50+5.00)= $7$

So $15$ $15$ pennies, $15$ $15$ dimes, $7$ $7$ quarters, and $20$ $20$ quarters is equivalent to $$ 7$ $$7$ .

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Question #c4c31

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