How many moles of water are produced when $"2.15 moles"$ of oxygen gas react with excess hydrogen gas?

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Answer 1 · 2017-10-23T05:41:16

$"4.30 moles"$

$"I mol"$ of $"O"_2$ produces $"2 moles"$ of $"H"_2"O"$ , so $"2.15 moles"$ of $"O"_2$ produce

$2/1×2.15 = "4.30 moles H"_2"O"$

How many moles of water are produced when "2.15 moles""2.15 moles" of oxygen gas react with excess hydrogen gas?