How do you graph the equation #x - 3y = 3#?
1 Answer
Nov 6, 2017
See a solution process below:
Explanation:
First, solve for two points which solve the equation and plot these points:
First Point: For
Second Point: For
We can next plot the two points on the coordinate plane:
graph{(x^2+(y+1)^2-0.025)((x-3)^2+y^2-0.025)=0 [-10, 10, -5, 5]}
Now, we can draw a straight line through the two points to graph the line:
graph{(x-3y-3)(x^2+(y+1)^2-0.025)((x-3)^2+y^2-0.025)=0 [-10, 10, -5, 5]}