If base of a triangle is #6.5# and its height is #6.5sqrt3#, what is its area?

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Answer 1 · 2017-11-15T04:37:41

Area is #(42.25sqrt3)/2# or #36.5885# square units

Area of any triangle is #1/2xx"Base"xx"Height"#

Here #"Base"=6.5#

#"Height"=6.5sqrt3#

Hence #"Area"=1/2xx6.5xx6.5xxsqrt3=(6.5^2xxsqrt3)/2#

#=(42.25sqrt3)/2#

#=(42.25xx1.732)/2=36.5885# square units

Answer 2 · 2017-11-15T04:38:27

It is #21.125sqrt3#.

The formula for the area of a triangle is:

#A=B*H/2#

where B is the base and H is the Height.

Therefore, in your problem:

#A=6.5*6.5sqrt3/2# =#21.125sqrt3#