Question

Question #6ef2d

Answer 1

`x=2`

Explanation:

`3x=xsum_(n=1)^2n`
`2x=xprod_(n=1)^2n`

`=>`
`3x-2x=xsum_(n=1)^2n-xprod_(n=1)^2n=x(sum_(n=1)^2n-prod_(n=1)^2n)=x`

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`1+1=2`

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`=>`
`3x-1=2x+1`
`=> 3x-2x=1+1`
`=> x=2`