Question #122ff

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Question #122ff

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Answer 1 · 2017-12-09T13:34:16

$\frac{7 π}{4}$ $(7pi)/4$

Explanation:

You can find the reference angle for the $θ$ $theta$ by calculating ${tan}^{- 1} (∣ ∣ ∣ \frac{b}{a} ∣ ∣ ∣)$ $tan^(-1)(|b/a|)$ , which in this case would give ${tan}^{- 1} (1) = \frac{π}{4}$ $tan^(-1)(1)=pi/4$ .

Knowing the reference angle we think about the quadrant in which the angle falls, which is QIV in this case. In QIV we find the actual angle by calculating $2 π - z$ $2pi-z$ , where $z$ $z$ is the reference angle. This give an angle of $\frac{7 π}{4}$ $(7pi)/4$ .

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Question #122ff

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