Question #e7817
1 Answer
Explanation:
Your unknown compound has
7 moles of carbon,7 xx "C" 8 moles of hydrogen,8 xx "H" x moles of oxygen,x xx "O"
This means that the molar mass of the compound can be calculated like this
M_"M" = overbrace(7 xx "12.011 g mol"^(-1))^(color(blue)("7 moles C")) + overbrace(8 xx "1.00794 g mol"^(-1))^(color(blue)("8 moles H")) + overbrace(x xx "15.9994 g mol"^(-1))^(color(blue)(x quad "moles O"))
M_"M" = (94.14052 + 15.9994 * x)quad "g mol"^(-1)
Now, you know that this compound contains
( 15.9994 * x color(red)(cancel(color(black)("g mol"^(-1)))))/((94.14052 + 15.9994 * x)color(red)(cancel(color(black)("g mol"^(-1))))) xx 100% = 26.2% This basically means that if you take the mass of oxygen present in
1 mole of this compound, divide it by the total mass of1 mole of the compound, and multiply the result by100% , you will end up with26.2% , the percent concentration by mass of oxygen.
You will thus have
(15.9994 * x)/((94.14052 + 15.9994 * x)) xx 100 color(red)(cancel(color(black)(%))) = 26.2color(red)(cancel(color(black)(%)))
Rearrange to solve for
15.9994 * 100 * x = 26.2 * 94.14052 + 26.2 * 15.9994 * x
x * 15.9994 * (100 - 26.2) = 26.2 * 94.14052
You will end up with
x = (26.2 * 94.14052)/(15.9994 * (100 - 26.2)) = 2.089 ~~ 2
You can thus say that you have