Question

Question #06104

Answer 1

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Refer to the figure above. Tractor is parked on the incline and is at rest. To keep it in the state of equilibrium, downward force along the incline `mgsintheta` should be balanced by the force of friction `f` given as `muN`.

`:.f=mgsintheta`
where `m` is mass of tractor, `g=9.81" ms"^-2` is acceleration due to gravity.

Inserting given values we get

`f=2000xx9.81xxsin25^@`
`=>f=8292" N"`