Question #2bc16

1 Answer
Jan 31, 2018

The points are: #(-5,8),(6,327)#

Explanation:

You do part b. the same way that you did part a. except that you set the first derivative equal to 144, instead of 0.

#f'(x) = 6x^2-6x-36 = 144#

#6x^2-6x-180 = 0#

#x^2-x-30 = 0#

#(x +5)(x-6) = 0#

#x = -5# and #x = 6#

The corresponding y coordinates are:

#f(-5) = 2(-5)^3+3(-5)^2-36(-5)+3# and #f(6) = 2(6)^3+3(6)^2-36(6)+3#

#f(-5) = 8# and #f(6) = 327#

The points are: #(-5,8),(6,327)#