Question #461b0

1 Answer
Feb 11, 2018

"0.31 g"

Explanation:

The idea here is that under STP conditions, which are defined as a pressure of "100 kPa" and a temperature of 0^@"C", 1 mole of any ideal gas occupies "22.71 dm"^3 -> this is known as the molar volume of a gas at STP .

Since you know that

"1 dm"^3 = 10^3 quad "cm"^3

you can say that at STP, 1 mole of any ideal gas occupies 2.271 * 10^4 "cm"^3.

You can use the molar volume of a gas at STP to find the number of moles of oxygen as present in your sample.

220 color(red)(cancel(color(black)("cm"^3))) * "1 mole O"_2/(2.271 * 10^4 color(red)(cancel(color(black)("cm"^3)))) = 9.687 * 10^(-3) quad "moles O"_2

To convert the number of moles of oxygen gas to moles, you can use the molar mass of oxygen gas.

9.687 * 10^(-3) color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2)))) = color(darkgreen)(ul(color(black)("0.31 g")))

The answer is rounded to two sig figs, the number of sig figs you have for the volume of oxygen gas.