82. Toilet bowl cleaners often contain hydrochloric acid to dis- solve the calcium carbonate deposits that accumulate with in a toilet bowl. How much calcium carbonate in grams can be dissolved by 5.8 g of HCl?

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82. Toilet bowl cleaners often contain hydrochloric acid to dis- solve the calcium carbonate deposits that accumulate with in a toilet bowl. How much calcium carbonate in grams can be dissolved by 5.8 g of HCl?

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Answer 1 · 2016-11-27T19:46:40

$C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + H_{2} O (l) + C O_{2} (g) ↑ ⏐$ $CaCO_3(s) + 2HCl(aq) rarr CaCl_2(aq) + H_2O(l) +CO_2(g)uarr$

Explanation:

The stoichiometrically balanced equation tells us that each equiv calcium salt requires 2 equiv hydrochloric acid for reaction to give SOLUBLE calcium chloride and carbon dioxide gas.

$Moles of HCl$ $"Moles of HCl"$ $=$ $=$ $\frac{5.8 \cdot g}{36.46 \cdot g \cdot m o l^{- 1}} = 0.159 \cdot m o l$ $(5.8*g)/(36.46*g*mol^-1)=0.159*mol$ .

And this will react with an equivalent mass of $C a C O_{3}$ $CaCO_3$ , here $0.159 \cdot m o l \times \frac{1}{2} \times 100.09 \cdot g \cdot m o l^{- 1} ≅ 8 \cdot g .$ $0.159*molxx1/2xx100.09*g*mol^-1~=8*g.$

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82. Toilet bowl cleaners often contain hydrochloric acid to dis- solve the calcium carbonate deposits that accumulate with in a toilet bowl. How much calcium carbonate in grams can be dissolved by 5.8 g of HCl?

1 Answer

Explanation:

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