A 0.310 mol sample of xenon gas has a volume of 22.0 L at a pressure of 0.470 atm. What is the temperature of the gas in degrees Celsius?

1 Answer

T=406.7 K

Explanation:

Given :

number of moles = n = 0.310 mol

Volume V = 22 L

Pressure P = 0.470 atm

Temperature T = ?

Gas constant , R , = 0.082 L atm mol1K1

Using gas equation ; PV=nRT

T=PVnR

T = 0.470 atm×22L0.082L atm mol1K1×0.310 mol

T=406.7 K