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A 175 mL sample of neon had its pressure changed from 75 KPa to 150 KPa. What is its new volume?

1 Answer

May 9, 2017

The new volume of the neon is: $V_{2} = 87.5 m L$ $V_2=87.5mL$

Explanation:

Boyle's law states that pressure is inversely proportional to volume for a fixed quantity of an ideal gas at a constant temperature.

The mathematical formula is : $V_{2} = \frac{P_{1} V_{1}}{P 2}$ $V_2=(P_1V_1)/(P2)$

Here we have: $P_{1} = 75 K P a; P_{2} = 150 K P a; V_{1} = 175 m L$ $P_1=75KPa; P_2=150KPa; V_1=175mL$

Then: $V_{2} = \frac{75 K P a \cdot 175 m L}{150 K P a}$ $V_2= (75KPa*175mL)/(150KPa)$

$V_2= (cancel(75KPa)1*175mL)/(cancel(150KPa)2)$

$V_2=87.5mL$

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