Question

A 2.0 L container of nitrogen had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 1 atm?

Answer 1

Given constant `T` and constant `n`, `P_1V_1=P_2V_2` so...........

Explanation:

`V_2=(P_1V_1)/P_2=(2.0*Lxx3.2*atm)/(1*atm)`

So, over `6*L?`

We assume here that the gas is enclosed in a piston, whose volume can be increased or decreased.