A 2.5 L container of xenon had a pressure change from 125 kpa to 35 kpa what is the new volume?

1 Answer
Jul 4, 2017

Roughly 8.9L

Explanation:

Assuming there is no temperature change then P1V1=P2V2, where the pressure (in Pa) x the volume in (m^3) is a constant.

In this case P1V1=P2V2((1251000)(2.50.001))=((351000)V2=(1250000.0025=35000V2.

V2=1250000.0025350000.0089m3=8.9L