A 2.6kg car is rolling down a frictionless incline that makes an angle of 23º to the horizontal. The initial speed of the car is 4.3m/s. What is the speed of the car 26m down the incline?

1 Answer
Jun 8, 2018

#v = 14.8 m/s#

Explanation:

The car's acceleration down the slope, #a_"ds"#, will be

#a_"ds" = g*sin23^@ = 3.83 m/s^2#

Using the formula #v^2 = u^2 + 2*a*d#,

#v^2 = (4.3 m/s)^2 + 2*3.83 m/s^2*26 m = 217.6 m^2/s^2#

#v = sqrt(217.6 m^2/s^2) = 14.8 m/s#

I hope this helps,
Steve