A 5.00 liter balloon of gas at 25 C is cooled to 0 C. What is the new volume (liters) of the balloon?

1 Answer
Dec 13, 2016

We use "Charles' Law"Charles' Law, V_1/T_1=V_2/T_2V1T1=V2T2

Explanation:

TT is specified to be "Absolute Temperature"absolute Temperature:

V_2=V_1/T_1xxT_2V2=V1T1×T2

= (5.00*L)/(298*K)xx273*K~=4.5*L=5.00L298K×273K4.5L