A 5 cm tall object is placed 68 cm from a convex mirror with a focal distance of -4 cm. The object is moved to 1cm from the same mirror. How would you calculate the distance to the image from the lens, the magnification, and the height of the image?
1 Answer
Explanation:
We can begin by using the mirror equation to calculate the distance from the image to the mirror.
#1/(f)=1/d_i+1/d_o# where
#f# is the focal length of the mirror,#d_i# is the distance from the image from the mirror, and#d_o# is the distance from the object to the mirror.
We are given that
#=(-1/4-1)^-1#
#=-4/5cm#
Therefore, the image is formed behind the mirror and is said to be a virtual image.
We can now use the values for
#m=-d_i/d_o#
#=-((-4/5))/1#
#=4/5#
Therefore, the image formed is reduced compared to the object size and upright.
Finally, we can use the values for
#m=h_i/h_o#
#=4/5*5#
#=4cm#