A .50 M solution of sodium thiosulfate, #Na_2S_2O_3#, is used to create a more dilute solution. If 250 mL of the concentrated solution is diluted to a volume of 2.5 L, determine the concentration of the new solution?

Question

11592 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-05T18:09:16

Th initial solution is diluted 10 fold, thus it is #0.050*mol*L^-1# after dilution.

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

#=# #(0.50*mol*L^-1xx0.250*L)/(2.50*L)# #=# #0.050*mol*L^-1# with respect to sodium thiosulate. What is the concentration with respect to sodium ion?