A 6 L container holds 5 mol and 6 mol of gasses A and B, respectively. Groups of three of molecules of gas B bind to two molecules of gas A and the reaction changes the temperature from 480^oK to 270^oK. How much does the pressure change?
1 Answer
the pressure change from
Explanation:
To calculate the initial pressure you can use the general law of perfect gasses: PV = nRT .
to know the final pressure, i suppose that there are still 3 moles of A, 3 moles of B and it was formed 1 mol of gas from the union of the moles reacted toward a total of 7 gass moles. The new pressure will be:
if instead all the molecules (6moles) of B react with the maximum possible number of the moles of A (4 moles, as the ratio is 3:2) at the end you will have still a mole of A and it was formed 2 moles of
I think that this second hypothesis is what is required