A 75.0 mL steel reaction vessel is filled with oxygen gas (O2) until the pressure reads 145 atm at 22C. How many moles of oxygen are in the container?

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A 75.0 mL steel reaction vessel is filled with oxygen gas (O2) until the pressure reads 145 atm at 22C. How many moles of oxygen are in the container?

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Answer 1 · 2017-09-06T04:50:03

Assuming ideality.....then approx. half a mole.......of $O_{2}$ $O_2$ ..

Explanation:

We assume ideality, and thus $n = \frac{P V}{R T}$ $n=(PV)/(RT)$

$= \frac{145 \cdot a t m \times 75.0 \cdot m L \times 10^{- 3} \cdot L \cdot m L^{- 1}}{0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 295.15 \cdot K}$ $=(145*atmxx75.0*mLxx10^-3*L*mL^-1)/(0.0821*(L*atm)/(K*mol)xx295.15*K)$

$= ? ? \cdot m o l$ $=??*mol$

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A 75.0 mL steel reaction vessel is filled with oxygen gas (O2) until the pressure reads 145 atm at 22C. How many moles of oxygen are in the container?

1 Answer

Explanation:

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