A 9.70 L container holds a mixture of two gases at 53C. The partial pressures of gas A and gas B, respectively, are 0.368 atm and 0.893 atm. If 0.210 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?

Question

A 9.70 L container holds a mixture of two gases at 53C. The partial pressures of gas A and gas B, respectively, are 0.368 atm and 0.893 atm. If 0.210 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?

1 Answer

Impact of this question

41756 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-09T09:47:42

This is an illustration of $Dalton's Law of Partial Pressures......$ $"Dalton's Law of Partial Pressures......"$

Explanation:

$Dalton's Law of Partial Pressures......$ $"Dalton's Law of Partial Pressures......"$ , $which states, that in a$ $"which states, that in a"$ $gaseous mixture, the partial pressure of a gaseous component is$ $"gaseous mixture, the partial pressure of a gaseous component is"$ $the same as the pressure it would exert if it alone occupied$ $"the same as the pressure it would exert if it alone occupied"$ $the container.$ $"the container."$

And thus $P_{mixture} = P_{A} + P_{B} + P_{c}$ $P_"mixture"=P_A+P_B+P_c$

We are given $P_{A}$ $P_A$ , and $P_{B}$ $P_B$ , but we must work out $P_{C}$ $P_C$ , which we can do by assuming ideality and employing the equation:

$P_{C} = \frac{0.210 \cdot m o l \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 326 \cdot K}{9.70 \cdot L} = 0.579 \cdot a t m .$ $P_C=(0.210*molxx0.0821*(L*atm)/(K*mol)xx326*K)/(9.70*L)=0.579*atm.$

And so..... $P_{mixture} = P_{A} + P_{B} + P_{c}$ $P_"mixture"=P_A+P_B+P_c$

$= (0.368 + 0.893 + 0.579) \cdot a t m$ $=(0.368+0.893+0.579)*atm$

$= 1.82 \cdot a t m .$ $=1.82*atm.$

Science

Math

Humanities

... and beyond

A 9.70 L container holds a mixture of two gases at 53C. The partial pressures of gas A and gas B, respectively, are 0.368 atm and 0.893 atm. If 0.210 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?

1 Answer

Explanation:

Related questions

Impact of this question