A balanced lever has two weights on it, one with mass $1 k g$ $1 kg$ and one with mass $4 k g$ $4 kg$ . If the first weight is $9 m$ $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-04-25T01:04:16

$2.25 \ "m"$

For a balanced lever, we have the following relationship:

$m_1d_1=m_2d_2$

$m_1,m_2$ are the masses of the two weights

$d_1,d_2$ are their distances from the fulcrum

And so, we get:

$1 \ "kg"*9 \ "m"=4 \ "kg"*d_2$

$d_2=(9color(red)cancelcolor(black)"kg""m")/(4color(red)cancelcolor(black)"kg")$

$=2.25 \ "m"$

A balanced lever has two weights on it, one with mass 1 kg1kg1 kg and one with mass 4 kg4kg4 kg. If the first weight is 9 m9m 9 m from the fulcrum, how far is the second weight from the fulcrum?