A balanced lever has two weights on it, one with mass $2 k g$ $2 kg$ and one with mass $15 k g$ $15 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-08-10T07:05:04

The distance is $= 0.4 m$ $=0.4m$

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The masses are

$M_{1} = 15 k g$ $M_1=15kg$

$M_{2} = 2 k g$ $M_2=2kg$

The distance $b = 3 m$ $b=3m$

Taking moments about the fulcrum

$M_{1} g \cdot a = M_{2} g \cdot b$ $M_1g*a=M_2g*b$

$a = \frac{M_{2}}{M_{1}} \cdot b = \frac{2}{15} \cdot 3 = 0.4 m$ $a=M_2/M_1*b=2/15*3=0.4m$

The distance is $= 0.4 m$ $=0.4m$

A balanced lever has two weights on it, one with mass 2 kg2kg2 kg and one with mass 15 kg15kg15 kg. If the first weight is 3 m3m 3 m from the fulcrum, how far is the second weight from the fulcrum?