A balanced lever has two weights on it, one with mass $4 kg$ and one with mass $2 kg$ . If the first weight is $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-04-01T03:37:29

$18 "m"$

To balance the lever, the torque about the fulcrum must be zero.

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In this question, we have

We want to find $b$ .

Therefore,

$(4 "kg") * (9 "m") = (2 "kg") * b$

$b = frac{(4 "kg") * (9 "m")}{2 "kg"}$

$= 18 "m"$

A balanced lever has two weights on it, one with mass 4 kg4 kg and one with mass 2 kg2 kg. If the first weight is 9 m 9 m from the fulcrum, how far is the second weight from the fulcrum?