A balanced lever has two weights on it, one with mass $6 k g$ $6 kg$ and one with mass $5 k g$ $5 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-07-09T07:54:59

The distance is $= 3.6 m$ $=3.6m$

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The mass $M_{1} = 6 k g$ $M_1=6kg$

The mass $M_{2} = 5 k g$ $M_2=5kg$

The distance $a = 3 m$ $a=3m$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot b$ $M_1*a=M_2*b$

$b = \frac{M_{1}}{M_{2}} \cdot a = \frac{6 g}{5 g} \cdot 3 = \frac{18}{5} = 3.6 m$ $b=M_1/M_2*a=(6g)/(5g)*3=18/5=3.6m$

A balanced lever has two weights on it, one with mass 6kg6 kg and one with mass 5kg5 kg. If the first weight is 3m 3 m from the fulcrum, how far is the second weight from the fulcrum?