A balanced lever has two weights on it, the first with mass $1 k g$ $1 kg$ and the second with mass $2 k g$ $2 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-12-29T04:40:25

Second weight is $2$ $2$ meters from the fulcrum.

In a balanced lever, which has two weights on it, the moment of the two weights is equal.

The moment is the product of the mass of the weight and its distance from fulcrum.

Hence as moment of first weight is $q \times 4 = 4$ $qxx4=4$ $k g . m$ $kg.m$ ,

distance of second weight of $2 k g$ $2kg$ is $\frac{4}{2} = 2$ $4/2=2$ meters from fulcrum.

A balanced lever has two weights on it, the first with mass 1kg1 kg and the second with mass 2kg2 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?