A balanced lever has two weights on it, the first with mass $1 k g$ $1 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-05-11T18:14:15

$x = 0.5 m$ $x=0.5 " "m$

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${\to G}_{1} = 1 \cdot 9.81 N$ $vec G_1=1*9.81 N$
${\to G}_{2} = 6 \cdot 9.81$ $vec G_2=6*9.81$

$1*cancel(9.81)*3=6*cancel(9.81)*x$

$x=3/6$

$x=1/2$

$x=0.5 " "m$

A balanced lever has two weights on it, the first with mass 1 kg 1kg1 kg and the second with mass 6 kg6kg6 kg. If the first weight is 3 m3m 3 m from the fulcrum, how far is the second weight from the fulcrum?