A balanced lever has two weights on it, the first with mass $1 k g$ $1 kg$ and the second with mass $5 k g$ $5 kg$ . If the first weight is $2 m$ $2 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-04-25T11:53:15

The distance is $= 0.4 m$ $=0.4m$

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The mass $M_{1} = 1 k g$ $M_1=1kg$

The mass $M_{2} = 5 k g$ $M_2=5kg$

The distance $a = 2 m$ $a=2m$

Taking moments about the fulcrum

$M_{1} \times a = M_{2} \times b$ $M_1xxa=M_2xxb$

$b = \frac{M_{1} \times a}{M_{2}} = \frac{1 \times 2}{5} = 0.4 m$ $b=(M_1xxa)/(M_2)=(1xx2)/(5)=0.4m$

A balanced lever has two weights on it, the first with mass 1kg1 kg and the second with mass 5kg5 kg. If the first weight is 2m 2 m from the fulcrum, how far is the second weight from the fulcrum?