A balanced lever has two weights on it, the first with mass $1 kg$ and the second with mass $5 kg$ . If the first weight is $2 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-04-25T11:53:15

The distance is $=0.4m$

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The mass $M_1=1kg$

The mass $M_2=5kg$

The distance $a=2m$

Taking moments about the fulcrum

$M_1xxa=M_2xxb$

$b=(M_1xxa)/(M_2)=(1xx2)/(5)=0.4m$

A balanced lever has two weights on it, the first with mass 1 kg 1 kg and the second with mass 5 kg5 kg. If the first weight is 2 m 2 m from the fulcrum, how far is the second weight from the fulcrum?