A balanced lever has two weights on it, the first with mass $1 k g$ $1 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $1 k g$ $1 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-02T19:43:00

0.33 m

Explanation:

The torque or moment of each of the weights about the fulcrum is equal because the lever is balanced.
Torque= Fd
F= mg
$m_{1} g d_{1} = m_{2} g d_{2}$ $m_1gd_1 = m_2gd_2$
F - Force (mass x gravitational
acceleration)
$d_{1} = m_{2} \frac{d_{2}}{m_{1}}$ $d_1 = m_2d_2/m_1$
(1kg)(3m)/9 kg

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A balanced lever has two weights on it, the first with mass $1 k g$ $1 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Explanation:

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A balanced lever has two weights on it, the first with mass $1 k g$ $1 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?