A balanced lever has two weights on it, the first with mass $1 kg$ and the second with mass $4 kg$ . If the first weight is $25 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-04-08T14:28:23

$6.25 \ "m"$

For a balanced lever, we have the following relationship:

$m_1d_1=m_2d_2$

$m_1,m_2$ are the masses of the two objects

$d_1,d_2$ are distances of the two objects from the fulcrum

And so,

$1 \ "kg"*25 \ "m"=4 \ "kg"*d_2$

$d_2=(1color(red)cancelcolor(black)"kg"*25 \ "m")/(4color(red)cancelcolor(black)"kg")$

$=6.25 \ "m"$

A balanced lever has two weights on it, the first with mass 1 kg 1 kg and the second with mass 4 kg4 kg. If the first weight is 25 m 25 m from the fulcrum, how far is the second weight from the fulcrum?